Question

find the cost of levelling the ground which is in the form of a triangle having length of its sides as 75m, 65m and 70 m at the rate of ₹5 per m2​

Answer 1

Answer:

we Can find by first finding the area then multiplying by cost per m2

Step-by-step explanation:

area of scalene triangle = s - 1/2 (side + side side )

√(s) (s - side) (s - side) ( s - side)

s = 1/2 (120)

s = 105

√(105) (105 - 70) (105 - 75) (100 - 65)

=√4410000

= 2,10,000

cost = 210000*50

= Rs. 1,05,00,000

HOPE THIS HELPS

Answer 2

Question:

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Find the cost leveling a ground in the form a traingle with sides 16 m, 12 m, 20 m at rs 4 per sq. meter.

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☯ Let sides of triangle be a, b and c.

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$\sf \therefore\;Sides_{\;\triangle} \begin{cases} & \sf{a = \bf{75\;cm}} \\ & \sf{b = \bf{65\;cm}} \\ & \sf{c = \bf{70\;cm}} \end{cases}$

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$\underline{\bigstar\:\boldsymbol{Using\: Heron's\:Formula\::}}$

$\star\;\sf s = semi - perimeter\\ \\ :\implies\sf s = \dfrac{a + b + c}{2}\\ \\ :\implies\sf s = \dfrac{75 + 65 + 70}{2}\\ \\ :\implies\sf s = \cancel{ \dfrac{210}{2}}\\ \\ :\implies{\boxed{\red{\sf{s = 105}}}}\;\bigstar$

Now, Area of triangle,

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$\star\;{\boxed{\sf{\purple{Area_{\;\triangle} = \sqrt{s(s - a)(s - b)(s - c)}}}}}$

$:\implies\sf \sqrt{105(105 - 75)(105 - 65)(105 - 70)}\\ \\ :\implies\sf \sqrt{105 \times 40 \times 40 \times 35}\\ \\ :\implies\sf {2\sqrt{105 \times 15 \times 2 \times 20 \times 2 \times 35}}\\ \\ :\implies\sf {2 \sqrt{1102500}}\\ \\ :\implies\sf \sqrt{2 \times (1050)^2 }\\ \\ :\implies\sf {2 \times 1050}\\ \\ :\implies{\boxed{\sf{\pink{2100\; m^2}}}}\;\bigstar$

$\therefore\;{\underline{\sf{Thus,\;Area\;of\;of\;ground\;is\; \bf{2100\;m^2}.}}}$

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Given that,

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Cost of per meter square = 5 Rs.

$\rightarrow$ Cost of 2100 m² = 5 × 2100 = 10500 Rs.

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$\therefore\;{\underline{\sf{Hence,\;Cost\;of\;of\;leveling\;ground\;is\; \bf{10500\;Rs}.}}}$