Question

Find the cost of lying grass in a triangular
field of side som, 65 m and 65 m at
the cate of 7per/m.(by heron's formula)​

Answer 1

Answer: 10500

Step-by-step explanation:

Since, ABC is a triangular field of sides

AB=a=50 m, BC=b=65 m and CA=c=65m.

∴Semi-perimeter of triangular field,

s=a+b+c2=50+65+652=1802

∴Area of a triangular field

=s(s−a)(s−b)(s−c)−−−−−−−−−−−−−−−−−√ [by Heron's formula]

=90(90−50)(90−65)(90−65)−−−−−−−−−−−−−−−−−−−−−−−−√

=90×40×25×25−−−−−−−−−−−−−−√

=3×2×10×25

=6×250=1500m2

∵cost of laying grass per 1m2=rupee 7

∵cost of laying grass per 1500m2=7×1500=rupee 10500

Hence, the cost of laying grass in a triangular field is rupee 10500.

Answer 2

Answer:

Given the sides are 65 m, 65 m, 65 m

Step-by-step explanation:

Perimeter=65+65+65=195

so one side s=195/2

=97.5 m

We know that s=√66+65+65

s=√195

s=√195×7

s= 97.74Rs

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