find the cost of painting 3 iron boxes at the rate of rupees 4.0 per square mtr whose dimension are 1.5 m* 0.60 m* 0.30m and 2m* 0.80m* 0.40m respectively
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Answer:
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Find the cost of painting 3 iron boxes at the rate of ₹4 per square metre, whose dimensions are 1.5m × 0.6m × 0.3m, 1.5m × 0.75m × 0.25m and 2m × 0.8m × 0.4 m respectively.
Let the three iron boxes be denoted as "Box 1", "Box 2" and "Box 3".
Dimension of Box 1 - 1.5m × 0.6m × 0.3m
Dimension of Box 2 - 1.5m × 0.75m × 0.25m
Dimension of Box 3 - 2m × 0.8m × 0.4 m
As it is given that the 3 iron boxes have to be painted so we will find the total surface area of each of the cuboidal shaped iron boxes.
Total Surface Area of a cuboid = 2(lb + bh + hl)
Total Surface Area of Box 1 = 2 [(1.5)(0.6) + (0.6)(0.3) + (0.3)(1.5)]
= 2[0.9 + 0.18 + 0.45]
= 3.06 m²
Total Surface Area of Box 2 = 2 [(1.5)(0.75) + (0.75)(0.25) + (0.25)(1.5)]
= 2[1.125 + 0.1875 + 0.375]
= 3.375 m²
Total Surface Area of Box 3 = 2 [(2)(0.80) + (0.80)(0.40) + (0.40)(2)]
= 2[1.6+0.32+0.8]
= 5.44 m²
Total Surface Area of all the boxes = 3.06 + 3.375 + 5.44
= 11.875 m²
The total cost of painting the 3 iron boxes is,
= 11.875 × 4
= Rs. 47.5
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