Find the cost of painting a hall of length 12m, breadth 6m, height 5m from inside along with its ceiling but not the floor at the rate of ₹50 per sq. m. PLS ANS STEP BY STEP.
Answers
Step-by-step explanation:
Length= 12m,
Breadth= 6m,
Height= 5m
We know,
LSA=2(l+b)×h
LSA=2×(12+6)×5
LSA = 54m²
Therefore, cost of painting = 54×50
= Rs.2700
Answer:
The cost of painting the hall is equal to ₹12600.
Step-by-step explanation:
We can consider the hall as a cuboid.
Given, the length of the hall, l = 12m
The breadth of the hall, b = 6m
The height of the hall, h = 5m
The total surface area of the hall = 2(lb + bh +hl)
TSA of the hall = 2 [(12)(6) + (6)(5) + (12)(5)]
TSA of the hall = 2 (72 + 30 + 60)
TSA of the hall = 2×162
TSA of the hall = 324 m²
The area of the floor = l×b = 12×6 = 72m²
Area of hall to be painted = TSA of the hall - area of the floor
Area of hall to be painted = 324 - 72 = 252m²
Given, the rate of painting = Rs.50 per m²
The cost of painting the hall = 50×252 = Rs.12600.
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