Question

Find the cost of painting a triangular metal sheet whose sides are in the ratio 5:12:13 having perimeter 300cm at the rate of rupees 3 per cm.sq

Answer 1

Answer:

$300 \times 3 = 900$

Step-by-step explanation:

if u multiple with 3you can get ur answer may be this answer will help u

Answer 2

It costs Rs 9000 to paint a triangular metal sheet

Solution:

Given that,

Sides of triangle are in ratio 5 : 12 : 13

Let one side be 5x

Let other side be 12x

Let the other side be 13x

Perimeter = 300cm

Perimeter of triangle = sum of all sides

300 = 5x + 12x + 13x

30x = 300

x = 10

Thus the length of sides are:

5x = 5(10) = 50

12x = 12(10) = 120

13x = 13(10) = 130

Find area of triangle

$Area\ of\ triangle = \sqrt{s(s-a)(s-b)(s-c)}$

Where,

a, b, c are sides of triangle

a = 50 ; b = 120 ; c = 130

s is half of perimeter

s = 300/2 = 150

Therefore,

$Area = \sqrt{150(150-50)(150-120)(150-130)}\\\\Area = \sqrt{150 \times 100 \times 30 \times 20}\\\\Area = 3000$

Thus area of triangle is 3000 sq cm

Find cost at 3 per cm.sq

Cost = 3000 x 3

Cost = 9000

Thus it costs Rs 9000 to paint a triangular metal sheet

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