Find the cost of painting of border of rectangular board of length 4m and breadth 2.5mat the rate of ₹ 120 per meter
Answers
Given Length of the room 6m
Given Breadth of the room = 4m
Given Height of the room = 2.5m
As the room is in a cuboidal shape therefore to find the cost of painting the walls at 25 per sq. m, We first need to find out the Area of four walls of the room
Lateral Surface area of Cuboid = Area of four walls of the room
Therefore, Lateral surface area or Area of four walls = 2/1 + b)h
where, I is the length, b is the breadth and h is the height of the room
put the given values of Ib and h in the formula.
=> 2(6+4)2.5
=> 2 x 10 x 2.5
=> 20 x 2.5
=>50sq.m
Now, Cost of painting 1 sq. m = 725
Cost of painting 50 sq. m 25 x 50 = 7
1250
Answer:
Length = 4m
Breadth = 2.5m
Perimeter of rectangle = 2(l+b)
=2(4+2.5)
= 13m
Cost of 1m = 120 Rs.
Cost of 13m = 120 × 13
= 1560 Rs.