Question

find the cost of painting the all round outer surface of a box with lid 60 cm long,40 cm wide and 30 cm high at 50 p per 20 cm sq

Answer 1

$\large{\boxed{\bold{Answer:}}}$

T. S. A of Cuboidal box = 2(lb+bh+hl)

$= 2(60 \times 40 + 40 \times 30 + 30 \times 60) \\ \\ = 2(2400 + 1200 + 1800) \\ \\ = 2(5400) \\ \\ = 10800c {m}^{2}$

Now finding the cost,

$20c {m}^{2} = 50 \: paisa \\ \\ = 1c {m}^{2} = \frac{50}{20} \: paisa \\ \\ = 10800c {m}^{2} = 27000 \: paisa \\ \\ = 270 \: rupees$

$\large{\boxed{\bold{Hope\:it\:helps\:you!}}}$

Answer 2

TSA of Box= 2(LB+BH+LH)
=2(2400+1200+1800)
=2(5400)
=10800 cm²

20cm²=50 paisa
1cm²=50/20 paisa
10800cm²=27000 Paisa
270 Rupees