find the cost of painting the all round outher surface of a box with lid 60cm Long 40cm wieght 30 cm hat 50 pasie per 20cm power 2
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Answered by
4
TSA of Box= 2(LB+BH+LH)
=2(2400+1200+1800)
=2(5400)
=10800 cm²
20cm²=50 paisa
1cm²=50/20 paisa
10800cm²=27000 Paisa
270 Rupees
=2(2400+1200+1800)
=2(5400)
=10800 cm²
20cm²=50 paisa
1cm²=50/20 paisa
10800cm²=27000 Paisa
270 Rupees
Answered by
1
l = 26cm
b = 26cm
h = 45cm
b = 26cm
h = 45cm
Anonymous:
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Mera matlab tha ki comment m question likh do...
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The dimension of an oil tin are 26cmx 26x45cm. find the area of tin sheet required for making 20 such tin if 1m square of tin sheet cast rupees 10 find the cast of tin used for these 20 tins.
Ok i am answering this question on the place of that answer
T.S.A of one tin = 2(lb+bh+lh)
= 2(26•26+26•45+26•45)
= 2(677+1170+1170)
= 2 × 3016
= 6032cm²
Sheet required for 20 such tins = 6032 × 20
= 120,640cm² = 12.06m²
rate .. 1m² = ₹20
then,
Cost = 20×12.06
= ₹ 241.2
= 2(26•26+26•45+26•45)
= 2(677+1170+1170)
= 2 × 3016
= 6032cm²
Sheet required for 20 such tins = 6032 × 20
= 120,640cm² = 12.06m²
rate .. 1m² = ₹20
then,
Cost = 20×12.06
= ₹ 241.2
means next line
thanks
You welcome
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