Question

Find the cost of painting the curved surface of a cylinder of base diameter 35 cm and height 20 cm at the rate of 20 paise per cm2.

Answer 1

Answer :

• Cost of painting the curved surface area of the cylinder is Rs. 44000

Explanation :

Given :

• Diameter of the cylinder, d = 35 cm
• Height of the cylinder, h = 20 cm

To find :

• Cost of painting the curved surface area of the cylinder.

Knowledge required :

Formula for Curved surface area of a cylinder :

⠀⠀⠀⠀⠀⠀⠀⠀⠀C.S.A. = 2πrh or πdh

Where,

• C.S.A. = Curved surface area of the cylinder
• r = Radius of the cylinder
• d = Diameter of the cylinder
• h = Height of the cylinder

Solution :

First let us find the curved surface area of the cylinder :

By using the formula for Curved surface area of a cylinder and substituting the values in it, we get :

⠀⠀=> C.S.A. = πdh

⠀⠀=> C.S.A. = 22/7 × 35 × 20

⠀⠀=> C.S.A. = 22 × 5 × 20

⠀⠀=> C.S.A. = 2200

⠀⠀⠀⠀⠀⠀⠀⠀⠀∴ C.S.A. = 2200 cm²

Hence the Curved surface area of the cylinder is 2200 cm².

Now let's find out the cost of painting the curved surface area of the cylinder.

To find out the cost of painting the cylinder we have to multiplying the curved surface area of the cylinder with the cost of painting per cm².

⠀⠀=> C.S.A × 20

⠀⠀=> 2200 × 20

⠀⠀=> 44000

⠀⠀⠀⠀⠀⠀⠀⠀⠀∴ Rs. 44000

Hence the cost of painting the curved surface area of the cylinder is Rs. 44000.

Answer 2

$\: \: \boxed{\boxed{\sf{\mapsto \: Firstly \: Let \: us \: understand}}}$

$\mathsf\red{C.S.A. \: of \: cylinder \: = \: 2πrh \: or \: πdh(2r \: = \: d)}$

$\texttt{r = Radius of the cylinder}$

$\texttt{d = Diameter of the cylinder}$

$\texttt{h = Height of the cylinder}$

$\: \: \boxed{\boxed{\sf{\mapsto \: From \: the \: question}}}$

$\mathsf\red{Given}$

$\mathsf{Diameter \: of \: cylinder \: = \: 35 \: cm}$

$\mathsf{Height \: of \: cylinder \: = \: 20 \: cm}$

$\mathsf{Cost \: of \: painting \: per \: {cm}^{2} \: = \: 20 \: paise}$

$\mathsf\red{● \: To \: find \: the \: cost \: of \: painting \: of \: CSA \: of \: cylinder}$

$\mathsf\green{CSA \: = \: πdh}$

$\mathsf\green{CSA \: = \: \frac{22}{7}×35×20}$

$\mathsf\green{CSA \: = \: 2200 \: {cm}^{2}}$

$\: \: \boxed{\boxed{\sf{CSA \: = \: 2200 \: {cm}^{2}}}}$

$\mathsf{Cost \: of \: painting \: of \: cylinder \: = 2200 {cm}^{2} \times 20}$

$\mathsf{=44000 {cm}^{2}}$

$\mathsf\red{\therefore \: The \: painting \: of \: cylinder \: costs \: = \: 44000 {cm}^{2}}$

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