find the cost of painting the four walls of a room at the rate of 35 per square metre whose perimeter of the base is 22 M and height is 5 M
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total area is 22*5 = 110
for 4 walls = 110*4 = 440
then the cost is 440*35 =15400
for 4 walls = 110*4 = 440
then the cost is 440*35 =15400
Nikki57:
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Hey!
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Perimeter of base = 22m
CSA of cuboid = 2h(l+b)
We know,
2(l+b) = Perimeter of rectangle
Perimeter = 22 m
So,
22×h
Height = 5m
= 22×5
CSA= 110 m^2
Cost of painting 1m^2= Rs.35
Cost of painting 110m^2= 110×35
= Rs.3,850 is the cost of painting 4 walls.
_______________________
Hope it helps...!!!
_______________________
Perimeter of base = 22m
CSA of cuboid = 2h(l+b)
We know,
2(l+b) = Perimeter of rectangle
Perimeter = 22 m
So,
22×h
Height = 5m
= 22×5
CSA= 110 m^2
Cost of painting 1m^2= Rs.35
Cost of painting 110m^2= 110×35
= Rs.3,850 is the cost of painting 4 walls.
_______________________
Hope it helps...!!!
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