Math, asked by ishu9880, 11 months ago

Find the cost of painting the outer curved surface area of hemispherical bowl radius 7 cm.if the rate of painting is Rs 2.50 per cm​

Answers

Answered by HiteshJoshi7
0

Answer:

Rs.770 ,I think

Step-by-step explanation:

c.s.a. of hemisphere =

2\pi {r}^{2}

=

2( \frac{22}{7} )(7)(7)

= 308 cm^2 is curved surface area of the hemisphere.

now rate of painting it= 308 × 2.50

= Rs.770

hope helps.

Happy New year

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