Find the cost of painting the outer surface of a closed box, which is 90 cm long. 60cm broad and 45 cm high, at the rate of 75 paise per20sq cm.
Answers
Answer:
658.125
Step-by-step explanation:
TSA of Cuboid = 2(lb+bh+hl)
Now , put the digits as given
Then answer comes = 17550 sq cm
17550 ÷ 20 = 877.5
Cost = 877.5 × .75 = 658.125 Answer
Answer: cost of painting = ₹911.25
Step-by-step explanation:
Total surface area of a cuboid =
2 * [ (l*b) + (b*h) + (l*h) ]
Where l = length of the cuboid
b = breadth of the cuboid
h = height of the cuboid
Given,
l = 90 cm; b = 60 cm; h = 45 cm
Using the formula and substituting the values, we get
Total Surface Area = 2 * [ (90*60) + (60*45) + (90*45) ]
=> 2 * [ 5400 + 2700 + 4050 ]
=> 2 * 12150
=> 24300 cm²
Cost of painting per 20 cm² = ₹0.75
Cost of painting 24300 cm² = (24300 * 0.75) / 20 = ₹911
Therefore the cost of painting = ₹911.25
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