Find the cost of painting the outer surface of a closed box which is 60cm long, 40cm broad and 30cm high at the rate of 50 paise per cm(sq)
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Answered by
15
L=60cm ,b= 40cm, h=30cm,
rate= 0.5 paise/cm²
Tsa of box=2(lb+bh+hl)
=10800cm²
Total cost=TSA * RATE
= 10800cm² * 0.5paise/cm²
After point removing...and cm² gets cancelled
= 10800 * 5paise/10
= 1080 * 5paise
=5400paise= 54 * 100 paise
Since, 1rs=100 paise
Then ,
Total cost = 54 rs
rate= 0.5 paise/cm²
Tsa of box=2(lb+bh+hl)
=10800cm²
Total cost=TSA * RATE
= 10800cm² * 0.5paise/cm²
After point removing...and cm² gets cancelled
= 10800 * 5paise/10
= 1080 * 5paise
=5400paise= 54 * 100 paise
Since, 1rs=100 paise
Then ,
Total cost = 54 rs
Answered by
5
l+b+h
60+40+30
130
130*50
6500
60+40+30
130
130*50
6500
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