Question

find the cost of painting the outer surface of a cuboidal house of length 15 CM breadth 12 m and height 9 M at rupees 45 per square metre

Answer 1

2(lb+bh+hl)
converting cm into m then 0.15m
2(0.15*12+12*9+9*0.15) solve it put and then multiply it by 45 u will get answer

Answer 2

for outer surface we take perimeter of cuboid which is =2(lb+bh+hl)
l=length= 15cm. =0.15m.
b=breadth = 12 cm.
h=height = 9 m.
then put all values in formula we get
=2(0.15×12+12×9+9×0.15)
=222.3 sq/m
then per square meter cost is 45 rs.
so the cost of 222.3 is 222.3×45=10003.5 Rs.