Find the cost of painting the outside of a rectangular box whose
length is 64cm, breadth is 54cm and height is 51cm, at the rate of
37 paisa per sq. m.
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Step-by-step explanation:
length l = 64 cm
breadth b = 54cm
height h = 51 cm
Total surface area of a cuboid is 2 (lb+bh+hl)
= 2 (64×54 + 54×51 + 51×64 )
= 2 (3456 + 2754 + 3264)
= 2 (9474)
= 18948 sq.cm
= 1.8948 sq.m
Cost of painting is 37 paise per sq.m
Cost of painting = 1.8948×37 = 70.1076 paise
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