Math, asked by akankshapathakknp, 1 year ago

Find the cost of painting the outside surface of a solid cylinder of diameter 14 m and height 21 m at rupees 8 per m2.

Answers

Answered by aliza9031
1

Answer:radius=d/2

radius=7/2  height=25m cost of painting =Rs/8

Total surface area = 2*pi*r(r+h)

=2*22/7*7/2(7/2+25)

=44/7*7/2( LCM=7/2+50/2)

=44/7*7/2*57/2 (simplification)

=11/1*1/1*57/1

=627sq.m

cost for painting=627*8

=5016Rs.

Step-by-step explanation:

radius=d/2

radius=7/2  height=25m cost of painting =Rs/8

Total surface area = 2*pi*r(r+h)

=2*22/7*7/2(7/2+25)

=44/7*7/2( LCM=7/2+50/2)

=44/7*7/2*57/2 (simplification)

=11/1*1/1*57/1

=627sq.m

cost for painting=627*8

=5016Rs.

Answered by harshchandolkar
0

Answer:

5016

Step-by-step explanation:

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