Find the cost of painting the outside surface of a solid cylinder of diameter 14 m and height 21 m at rupees 8 per m2.
Answers
Answered by
1
Answer:radius=d/2
radius=7/2 height=25m cost of painting =Rs/8
Total surface area = 2*pi*r(r+h)
=2*22/7*7/2(7/2+25)
=44/7*7/2( LCM=7/2+50/2)
=44/7*7/2*57/2 (simplification)
=11/1*1/1*57/1
=627sq.m
cost for painting=627*8
=5016Rs.
Step-by-step explanation:
radius=d/2
radius=7/2 height=25m cost of painting =Rs/8
Total surface area = 2*pi*r(r+h)
=2*22/7*7/2(7/2+25)
=44/7*7/2( LCM=7/2+50/2)
=44/7*7/2*57/2 (simplification)
=11/1*1/1*57/1
=627sq.m
cost for painting=627*8
=5016Rs.
Answered by
0
Answer:
5016
Step-by-step explanation:
mark me as a brainliest answer pls
Similar questions
Business Studies,
6 months ago
Art,
6 months ago
Chinese,
6 months ago
Math,
1 year ago
English,
1 year ago
Accountancy,
1 year ago
Math,
1 year ago