find the cost of painting the walls of a room at rupees 25 per square metre if Length breadth and height of a room has 6 m, 4 m and 2.5 M respectively
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Given Length of the room = 6m
Given Breadth of the room = 4m
Given Height of the room = 2.5m
As the room is in a cuboidal shape therefore to find the cost of painting the walls at ₹25 per sq. m, We first need to find out the Area of four walls of the room
Lateral Surface area of Cuboid = Area of four walls of the room
Therefore, Lateral surface area or Area of four walls = 2(l + b)h
where, l is the length, b is the breadth and h is the height of the room
put the given values of l,b and h in the formula.
=> 2(6 + 4)2.5
=> 2 × 10 × 2.5
=> 20 × 2.5
=> 50 sq. m
Now, Cost of painting 1 sq. m = ₹25
Cost of painting 50 sq. m = 25 × 50 = ₹ 1250
Given Breadth of the room = 4m
Given Height of the room = 2.5m
As the room is in a cuboidal shape therefore to find the cost of painting the walls at ₹25 per sq. m, We first need to find out the Area of four walls of the room
Lateral Surface area of Cuboid = Area of four walls of the room
Therefore, Lateral surface area or Area of four walls = 2(l + b)h
where, l is the length, b is the breadth and h is the height of the room
put the given values of l,b and h in the formula.
=> 2(6 + 4)2.5
=> 2 × 10 × 2.5
=> 20 × 2.5
=> 50 sq. m
Now, Cost of painting 1 sq. m = ₹25
Cost of painting 50 sq. m = 25 × 50 = ₹ 1250
Cubingwitsk:
Awesome Answer @Avreen ma'am :clap:
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