find the cost of plastering in the inner surface of the wall at rupees 9.50 per metre square is 21 m Deep and it has a diameter of its top is 6 metre
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Answered by
46
Answer:
Rs. 3762
Step-by-step explanation:
Inner surface of well = πdh
d = diameter of well = 6m
h = height of well = 21m
Calculating inner surface area from above formula
we get Inner Surface = 22 * 6 * 21 / 7 = 396 square meter
Cost of plastering per square meter = Rs. 9.5
Total cost of plastering inner surface = inner surface area * cost per meter square
= 396 * 9.5 = Rs. 3762
Answered by
17
if shape of well = shape of cylindrical tank
diameter = 6 m , radius = 6/2 = 3m
depth of well h = 21m
then,
area of the inner surface of well
= CSA of well + area of lower circular end of well
= 2πrh + πr^2 = πr( 2h + r)
= 22×3/7 ( 2×21 + 3 )
= 66 × 45/ 7 = 2970/ 7 m^2
cost of 1 m^2 = ₹9.50
cost of plastering inner surface area of the well = 9.50 × 2970/7
= ₹4030.7
second case:
it often seen that lower part of well remains unplastered so thus there is no need to plaster lower end of well. in that case
inner surface area
= 2πrh
= 2×22 × 3 × 21/ 7
= 396m^2
cost of 1 m^2 = ₹9.50
cost of plastering the inner surface of well = 9.50 × 396 = ₹3762
Answer:₹3762
diameter = 6 m , radius = 6/2 = 3m
depth of well h = 21m
then,
area of the inner surface of well
= CSA of well + area of lower circular end of well
= 2πrh + πr^2 = πr( 2h + r)
= 22×3/7 ( 2×21 + 3 )
= 66 × 45/ 7 = 2970/ 7 m^2
cost of 1 m^2 = ₹9.50
cost of plastering inner surface area of the well = 9.50 × 2970/7
= ₹4030.7
second case:
it often seen that lower part of well remains unplastered so thus there is no need to plaster lower end of well. in that case
inner surface area
= 2πrh
= 2×22 × 3 × 21/ 7
= 396m^2
cost of 1 m^2 = ₹9.50
cost of plastering the inner surface of well = 9.50 × 396 = ₹3762
Answer:₹3762
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