find the cost of ploughing a field at the rate of ₹20 per sq m if dimensions of the triangular plot area 120 m, 160m and 200m
Answers
given:-
dimensions of the triangular field 120m, 160m and 200m
here we have to find the cost of ploughing it @ 20 rupees per m²
so first of all, we have to find it's area.
let the sides be a, b and c respectively.
semi-perimeter = (120 + 160 + 200)/2
= 480/2
= 240m
using heron's formula = √s(s - a)(s - b)(s - c)
= √[240(240 - 120)(240 - 160)(240 - 200)]
= √(240 × 120 × 80 × 40)
= √(2 × 2 × 2 × 2 × 3 × 5 × 2 × 2 × 2 × 3 × 5 × 2 × 2 × 2 × 2 × 5 × 2 × 2 × 2 × 5)
= √(2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 3 × 3 × 5 × 5 × 5 × 5)
= 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 3 × 5 × 5
= 9600m²
the area of the triangular field is 9600m²
hence total cost @ rupees 20 per m² = 20 × 9600
= rupees 192000
Answer :- 9600m²
Sides :-
120m
160m
200m
S (semiperimeter) = 120+160+200/2
480/2
240 m
Using Herons Formula
√(240×120×80×40)
By solving it we have
2×2×2×2×2×2×2×2×3×5×5
= 9600m²