Find the cost of polishing a circular table-top of circumference 2.8m, if the rate of polishing is Rs $25/m^2 . (Take π = 3.14)
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Answer:
$15.6051
Step-by-step explanation:
Let the radius be r
Then,2πr=2.8
Or,2×3.14.r=2.8
Or,r=0.4458599
Area=πr^2=3.14×0.4458599×0.4458599=0.6242069m^2
Cost=25×0.6242069=$15.6051
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