Question

Find the cost of polishing a circular table-top of diameter 1.6 m, if the rate of polishing is ₹15/m2. (Take π = 3.14)

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Answer 1

____HEY MATE ___

Refer to the attachment above...

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Answer 2

$\bf{\Huge{\underline{\boxed{\bf{\green{ANSWER\::}}}}}}$

$\bf{\Large{\underline{\bf{Given\::}}}}}}$

A circular table - top of diameter 1.6m, if the rate of polishing is ₹15/m².

$\bf{\Large{\underline{\bf{To\:find\::}}}}}}$

The cost of polishing table.

$\bf{\Large{\underline{\boxed{\rm{\red{Explanation\::}}}}}}$

We have,

$\rm{The\:diameter\:of\:circular\:table-top\:=\:1.6m}$

We know that radius of circle = $\sf{\frac{Diameter}{2} }$

So,

$\leadsto\rm{Radius\:=\:\frac{1.6*10}{2*10} =\cancel{\frac{16}{20} }}$

$\leadsto\rm{Radius\:=\:\frac{4}{5}m }$

We know that area of circle: $\rm{\orange{\pi r^{2} }}$

$\longmapsto\rm{Area\:of\:table-top\:=\:\pi r^{2} }$

$\longmapsto\rm{Area\:of\:table-top\:=\:[3.14*(\frac{4}{5} )^{2} ]m^{2} }$

$\longmapsto\rm{Area\:of\:table-top\:=\:(3.14*\frac{16}{25} )m^{2} }$

$\longmapsto\rm{Area\:of\:table-top\:=\:\cancel{(\frac{50.24}{25} )}m^{2} }$

$\longmapsto\rm{Area\:of\:table\:top\:=\:\orange{{2.0096m^{2} }}}$

Now,

$\rm{Cost\:of\:polishing\:1m^{2} \:area\:=\:Rs.15}$

$\rm{Cost\:of\:polishing\:2.0096m^{2} \:area\:=\:Rs.(15*2.0096)}$

$\rm{Cost\:of\:polishing\:2.0096m^{2} \:area\:=\:Rs.30.144}$

Thus,

$\rm{\red{The\:cost\:of\:polishing\:a\:circular\:table-top\:=\:{\orange{Rs.30.14}}}}$  [approx]