find the cost of polishing a circular table top of diameter =1•6m,if the rate of polishing is Rs 15/m2 (take pi=3•14)
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In this question, we will find area of table first i.e. 3.14 *1.6/2*1.6/2 = 2.0096 sq m
Now, at the rate of Rs 15 per m^2 , total cost of polishing = Rs 15*2.0096 = Rs 30.144.
Now, at the rate of Rs 15 per m^2 , total cost of polishing = Rs 15*2.0096 = Rs 30.144.
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area of circle= πr^2
diameter of table= 1.6m
radius of table= 0.8m
Area = 3.14× (0.8)^2
=3.14×0.64=2.0096m^2
cost of polishing= 2.0096×15=30.14Rs
diameter of table= 1.6m
radius of table= 0.8m
Area = 3.14× (0.8)^2
=3.14×0.64=2.0096m^2
cost of polishing= 2.0096×15=30.14Rs
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