Question

Find the cost of polishing a circular table-top of diameter 1.6 the rate of polishing is rupees 15/m2.(take π=3.14)

Answer 1

Radius = 1.6/2
= 0.8
area o table top =pi*r²
= 3.14*(0.8)²
=2.0096 m²
Cost = 2.0096*15= Rs 30.144

Answer 2

$\huge\mathfrak{\underline{Correct\:question}}$

Find the cost of polishing a circular table-top of diameter 1.6 m, if the rate of polishing is ₹15/m2. (Take π = 3.14)

_____________________________

Given that:-

• Diameter of circular table-top.

• Rate of polishing is rupees = 15/m^2

To find:-

• Cost of polishing.

•We have to take[ π = 3.14]

Answer:-

$\bold{STEP-BY-STEP-EXPLANATION}$

From the question it is given that,

Diameter of the circular table-top = 1.6 m

We know that, radius (r) = d/2

= 1.6/2

= 0.8 m

Then,

Area of the circular table-top = πr2

= 3.14 × 0.82

= 3.14 × 0.8 ×0.8

= 2.0096 m^2

Cost for polishing 1 m^2 area = ₹ 15 [As given]

Cost for polishing 2.0096 m^2 area = ₹ 15 × 2.0096

= ₹ 30.144

Hence, the Cost for polishing 2.0096 m^2 area is ₹ 30.144.

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