Question

Find the cost of polishing a circular tabletop of diameter 2.2 m if the rate of polishing is
20/m².(Take = 3.14)​

Answer 1

Answer:

Area of tabletop =πr²(r=2.2/2=1.1)

=3.14×1.1×1.1

=3.7994 m²

cost of polishing= 20×3.7994

=75.988Rs.

Answer 2

Given: diameter of tabletop 2.2m

Step-by-step explanation:

Area of tabletop = πr²

r = 22/2

r = 1.1

Area = π r²

3.14× 1.1 × 1.1

= 3.7994m²

cost of polishing pee meter is 20 rupees

so cost of polishing 3.7994 m²

= 20×3.7994

= 75.988 rupees