Question

Find the cost of polishing a rhombus shaped table with diagonal 4.6m and 6.8m. The rate of polishing is 20 rupees per m2​

Answer 1

Step-by-step explanation:

diagonal d1=4.6m

diagonal d2=6.8

area of rhombus =1/2 d1×d2

=1/2×4.6×6.8

=15.64 m^2

rate of polishing =rs 20 per m2

i.e 1m^2=rs 20

15.64m^2=rs 20 ×15.64

=rs 312.8

Answer 2

Answer:

Rs 312.80

Step-by-step explanation:

area of a rhombus = 1/2(d1 × d2)

where d1 and d2 are the diagonals

area = 1/2(4.6 × 6.8)

        = 15.64

cost of polishing = area × cost per unit²

                            = 15.64 × 20

                            = Rs 312.8

                            = 312 rupees and 80 paise