Question

Find the cost of polishing on a cylindrical tower with radius 7cm and height 15cm at a

rate of Rs. 5 per cm2

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Answer 1

The surface area of cylinder

$s = 2\pi \: rh \\ s = 2 \times \frac{22}{7} \times 7 \times 15 \\ s = 660 \: {cm}^{2}$

The cost of polishing on a cylindrical tower with radius 7cm and height 15cm at a rate of Rs. 5 per cm2

660*5 = Rs 3300

Answer 2

Answer:

Step-by-step explanation:

₹ 705.60

Step-by-step explanation:

Sides of a triangle are:

A – 9

B-28

C-35

S = a+ b+ c/2

=9+28+35/2

=72/2 =36 cm

Area of triangle = √s(s-a)(s-b)(s-c)

=√ 36(36-9)(36-28)(36-35) cm²

=√36*27*8*1 cm²

=3*2*3*2√3*2 cm²

=36√6 cm²

=(36*2.45) cm ²

=88.2 cm² (apx)

Area of 16 triangles  

= (16*88.2) cm²

=1411.2 cm²

Rate of polishing = ₹ 0.5 /cm²

=(0.5*1411.2)=₹ 705.60

Hope it helps

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