Find the cost of polishing on a cylindrical tower with radius 7cm and height 15cm at a
rate of Rs. 5 per cm2
Answers
Answer:
we know the height in 15cm
and radius is 7cm
Now the CSA of the cylinder is
2x22/7×7×15
=660m²
Now we know that the cost of polishing per m² is 5 rupees
Now 660x5
=3300
Therefore the cost of polishing the cylindrical tower is
rupees 3300.
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Answer:
Step-by-step explanation:
₹ 705.60
Step-by-step explanation:
Sides of a triangle are:
A – 9
B-28
C-35
S = a+ b+ c/2
=9+28+35/2
=72/2 =36 cm
Area of triangle = √s(s-a)(s-b)(s-c)
=√ 36(36-9)(36-28)(36-35) cm²
=√36*27*8*1 cm²
=3*2*3*2√3*2 cm²
=36√6 cm²
=(36*2.45) cm ²
=88.2 cm² (apx)
Area of 16 triangles
= (16*88.2) cm²
=1411.2 cm²
Rate of polishing = ₹ 0.5 /cm²
=(0.5*1411.2)=₹ 705.60
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