Question

Find the cost of polishing the Rhombus shaped tile with diagonals 1.6m and 2.8m
The rate of polishing is Rs. 20 per 100 sq.cm

Answer 1

Step-by-step explanation:

area of rhombus =1/2×products of its diagonals

=1/2×1.6×2.8

=2.24m^2

=2.24×100×100

22400cm^2

Rs20=100cm^2

1cm^2=Rs20/100

22400cm^2= Rs20/100×22400

=20×224

Rs4480 Ans

Answer 2

MARK ME AS THE BRAINLIEST

Answer:

₹1,12,000

Step-by-step explanation:

area of rhombus = 1/2×d1×d2

= 1/2×1.6×2.8 m^2

= 2.24 m^2

= 22400 cm^2

cost of polishing 100 cm^2 = ₹20

cost of polishing 1 cm^2 = 100/20 = ₹5

cost of polishing 22400 cm^2 = 22400×5

= ₹1,12,000

HOPE IT IS USEFUL