Question

find the cost of polishying a circular table top at a rate of 5/m2 if tbe circumference of that circular table is 154 cm​

Answer 1

Answer:

Circumference= 154 cm

so,

$2 \: \pi \: r = 154 \: cm \\ 2 \times \frac{22}{7} \times r = 154 \\ r = \frac{154 \times 7}{22 \times 2} \\ r = \frac{7 \times 7}{2}$

now, we got the radius as (7*7)/2 cm

for Area of the circular table

$area \\ = \pi {r}^{2} \\ = \frac{22}{7} \times \frac{7 \times7 }{2} \times \frac{7 \times 7}{2} \\ = \frac{3773}{2} {cm}^{2}$

for cost

cost= area * rate

$cost = \frac{3773}{2} \times 5 \\ = rs. \: 9,432.50$

answer: Cost of polishing the circular surface is Rs.9,432.50

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