Question

Find the cost of repairing a 25m wide hall whose perimeter is 300m, at the rate of Rs. 2/m^2​

Answer 1

Answer:

first of all we should find the height of the hall

width=25m

perimeter=300m

the hall is obviously a rectangle

perimeter of rectangle= 2(height+width)

300m=2(height+25m)

300/2=height+25

height=125-25

height=100m

area of the hall= height×width

area of the hall= 100×25

area of the hall= 2500 square metre

cost of repairing 1 square metre= Rs 2

cost of repairing 2500 square metre= 2500×2

cost repairing the hall= Rs 5000

Answer 2

Answer:

Rs . 5000 I am sure ............