Find the cost of sinking a tubewell 280 m deep, having diameter 3 m at the rate of Rs. 3.60 per cubic metre. Find also the cost of cementing its inner curved surface at Rs. 2.50 per square metre.
Answers
Given : Depth of tubewell = 280 m
Diameter of tubewell = 3 m
Radius of tubewell = 3/2 m
Volume of tubewell ,V = πr²h
V = 22/7 × (3/2)² × 280
V = 22/7 × 9/4 × 280
V = 22 × 9 × 10
Volume of tubewell,V = 1980 m³
Curved surface area of tubewell , C.S.A = 2πrh
C.S.A = 2 × 22/7 × 3/2 × 280
C.S.A = 22 × 40 × 3
C.S.A = 66 × 40
C.S.A of tubewell = 2640 m²
cost of sinking a tubewell at the rate of = ₹ 3.60/m³
Cost of sinking a tubewell = Rate × volume
= 3.60 × 1980
= ₹ 7128.
Hence, the cost of sinking a tubewell is ₹ 7128
Cost of cementing its inner curved surface at the rate of = ₹ 2.50 per square metre.
Ccost of cementing = Rate × inner curved surface
= 2.50 × 2640
= ₹ 6600.
Hence , the cost of cementing its inner curved surface is ₹ 6600.
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Answer:
Step-by-step explanation:
Volume of tubewell ,V = πr²h
V = 22/7 × (3/2)² × 280
V = 22/7 × 9/4 × 280
V = 22 × 9 × 10
Volume of tubewell,V = 1980 m³
Curved surface area of tubewell , C.S.A = 2πrh
C.S.A = 2 × 22/7 × 3/2 × 280
C.S.A = 22 × 40 × 3
C.S.A = 66 × 40
C.S.A of tubewell = 2640 m²
cost of sinking a tubewell at the rate of = ₹ 3.60/m³
Cost of sinking a tubewell = Rate × volume
= 3.60 × 1980
= ₹ 7128.