Question

Find the cost of sinking a tubewell 280m deep, having diameter 3m at the rate of Rs 3.60 per cubic metre . Also find the cost of cementing its inner curved surface at Rs 2.50 per square metre.

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Answer 1

Answer:

Given:

⇏ A tube well 280 m deep having diameter 3 m at the rate of Rs.3.60 per m³.

Find:

⇏ Find the cost of sinking a tubewell 280m deep, having diameter 3m at the rate of Rs 3.60 per cubic metre and find the cost of cementing its inner curved surface at Rs 2.50 per square metre.

Calculations:

⇏ $\sf Volume = 3.14 \times (1.5) {}^{2} × 280$

⇏ $\sf Volume = 1978.2 m {}^{2}$

Finding the cost of sinking:

⇏ $\sf 3.60 \times 1978.2$

⇏ $\sf 7121.52$

Therefore, 7121.52 is the cost of sinking.

Finding the inner curved surface area:

⇏ $\sf CSA = 2πrh$

⇏ $\sf CSA = 2 \times 3.14 \times 1.5 \times 280$

⇏ $\sf CsA = 2637.6 m {}^{2}$

Therefore, 2637.6 m² is the curved surface area.

Finding the cost of cementing:

⇏ $\sf 2.50 \times 2637.6$

⇏ $\sf 6594$

Therefore, 6594 is the cost of cementing.

Answer 2

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$\huge\tt{TO~FIND:}$

• Find the cost of sinking a tubewell 280m deep, having diameter 3m at the rate of Rs 3.60 per cubic metre .
• Also find the cost of cementing its inner curved surface at Rs 2.50 per square metre.

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$\huge\tt{SOLUTION:}$

VOLUME OF TUBEWELL

↪Volume = 22/7× 3 × 280

↪Volume = 1978.2m³

↪Cost Of sinking = 3.60 × 1978.3

↪Cost Of sinking = ₹ 7121.52

HENCE,VOLUME OF TUBEWELL IS 1978.2 M³ & COST OF SINKING IT IS ₹ 7121.52

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Inner curve surface area = 2πrh

Inner curve surface area = 2 × 22/7 × 1.5 × 280

Inner curve surface area = 2637.6m²

Cost of cementing = 2.50 × 2637.6

Cost of cementing = ₹6594

HENCE,THE INNER RADIUS IS 2637.6 M² AND COST OF CEMENTING IT IS ₹ 6594

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