Question

find the cost of the flooring a room 7.5 metre by 6 metre square tiles of side 30cm at the rate rs 6 pr tiles.​

Answer 1

Answer:

₹3000

Step-by-step explanation:

Area of flooring :

$\implies$ $A=l×b$

$\implies$ $A=7.5×6$

$\implies$ $A=45\:m^{2}$

Area of square tiles :

$\implies$ $A=l^{2}$

$\implies$ $A=0.3×0.3$ (30cm = 0.3m)

$\implies$ $A=0.09\:m^{2}$

No. of tiles :

$\implies$ $Tiles=\Large\frac{A\:of\:floor}{A\:of\:tiles}$

$\implies$ $Tiles=\Large\frac{45}{0.09}$

$\implies$ $Tiles=500$

Cost of tiles :

$\implies$ $Cost=500×6$

$\implies$ $\boxed{Cost=3000\:Rupees}$

Flooring of the room costs ₹3000.

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Answer 2

SOLUTION:-

Given:

The flooring a room is 7.5m by 6m square tiles of side 30cm at the rate of Rs.6/tiles.

To find:

The cost of the flooring a room.

Explanation:

We have,

• Length of the floor,L= 7.5m
• Breadth of the floor,B= 6m

In metres:

Length of floor= 7.5×100= 750cm.

Breadth of floor= 6×100= 600cm.

Area of the floor: Length × Breadth

Area of the floor= 750cm × 600cm

Area of the floor= 450000cm².

&

Length of each side of Square tile=30cm

Area of square tile= [Side]²

Area of Square tile= [30cm]²

Area of square tile= 900cm².

Now,

Number of tiles:

$\frac{Area \: of \: floor}{Area \: of \: one \: tile} = \frac{450000}{900} \\ \\ Number \: of \: tiles = 500$

Cost of 1 tile is Rs.6

Cost of 500 tiles= Rs.(6 × 500)

Cost of 500 tiles= Rs.3000.