Question

find the cost of tilling the floor of a trapezoidal hall whose parallel sides are 25m and 20m and the distance between them is 16m ath the rate of ₹ 40m2​

Answer 1

Given :-

Parallel sides of trapezoidal hall = 25m and 20m

The distance between them = 16m

Answer :-

Parallel sides = 25m and 20m

Height = 16m

Area of trapezium = 1/2 * h * ( a + b)

Put the required values in the formula,

Area of trapezium = 1/2 * 16 * ( 25 + 20 )

Area of trapezium = 1/2 * 16 * 45

Area of trapezium = 8 * 45

Area of trapezium = 360m^2

Cost of per m^2 = ₹40

Therefore,

Cost of 360m^2 = 360 * 40

Cost of 360m^2 = 14400

Therefore,

The cost of tilling the floor is ₹14400

Answer 2

Given :

• Parallel sides of trapezium = 25 m and 20 m.
• Height (Distance between the two parallel sides) = 16 m
• Cost of per m² = Rs. 40

To Find :

• The cost of tilling the floor of a trapezoidal hall = ?

Solution :

First of all let's find the area of trapezoidal hall :

→ Area of trapezium = ½ × (Sum of parallel sides) × Height

→ Area of trapezium = ½ × (25 + 20) × 16

Dividing 16 by 2 we get :

→ Area of trapezium = (25 + 20) × 8

→ Area of trapezium = 45 × 8

Multiply 45 by 8 we get :

→ Area of trapezium = 360 m²

• Hence,the area of trapezoidal hall is 360 m².

Finding cost of tilling the floor :

➻ Cost of per m² = Rs. 40

➻ Cost of 360 m² = 360 × 40

➻ Cost of 360 m² = Rs. 14400

• Hence,the cost of tilling the floor would be Rs. 14400.