Find the cost of turfing a triangular field at the rate of 5/m2 having lengths of its sides as 40 m, 70 m and 90 m.(Take √5 = 2.24)
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Answered by
19
FOR TURFING.....
AREA OF TRIANGLE = BY HERONS FORMULA.....
S=40+70+90/2
S=200/2
S=100
AREA = √S(S-A)(S-B)(S-C)
AREA=√100(100-40)(100-70)(100-90)
AREA=√100*60*30*10
AREA= √1800000
AREA =1341.640....
AREA = 1341.640m2
NOW COST IS 5 PER M2
SO MULTIPLY THE AREA BY 5 ....
1341.640*5
6708.2
so the cost of turfing is 6708.2rs.....
hope it will help you......☺
AREA OF TRIANGLE = BY HERONS FORMULA.....
S=40+70+90/2
S=200/2
S=100
AREA = √S(S-A)(S-B)(S-C)
AREA=√100(100-40)(100-70)(100-90)
AREA=√100*60*30*10
AREA= √1800000
AREA =1341.640....
AREA = 1341.640m2
NOW COST IS 5 PER M2
SO MULTIPLY THE AREA BY 5 ....
1341.640*5
6708.2
so the cost of turfing is 6708.2rs.....
hope it will help you......☺
shivanivinod2004:
Actually what is turfing ?
dont you think it should be done this way ?
√100*60*30*10 = 10√3*2*10*3*10*10 = 10*10*3√2*2*5 = 10*10*3*2√5= 600√5 = 600*2.24 = 1344m^2 and thus cost = 1344*5 = Rs.6720
no its wrong how can u write 60 as 10*2*√3
no
wait .. just see the question..u need to use 2.24 in place of √6 somewhere. You havent used 2.24 at all. Youve just done √1800000 in decimal form. Clarify once more
yes I know ......but its a pro of maths.....so it can be solved by many methods..... I just solved it by another method
and the question of root is still constant
:(
Answered by
4
Answer:
FOR TURFING.....
AREA OF TRIANGLE = BY HERONS FORMULA.....
S=40+70+90/2
S=200/2
S=100
AREA = √S(S-A)(S-B)(S-C)
AREA=√100(100-40)(100-70)(100-90)
AREA=√100*60*30*10
AREA= √1800000
AREA =1341.640....
AREA = 1341.640m2
NOW COST IS 5 PER M2
SO MULTIPLY THE AREA BY 5 ....
1341.640*5
6708.2
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