Question

Find the cost of watering a trapezoidal field whose parallel sides are 10 m and 25 m respectively. If the distance between them is 15 cm and the rate of watering is rs 4 per m square.

Answer 1

Area of Trapezium Field = 1/2*(Sum Of Sides)*height 
                                        =1/2*(25+10)*15
                                        =1/2*35*15
                                        =262.5 m square
Cost of Watering =Area* Cost of 1 m square
                            =262.5*4
                            =1050 Rs

Answer 2

The cost of watering the trapezoidal field is 21 rs.

The trapezoidal field has a parallel sides of 10 m and 25 m, and the distance between them is 15 cm.

To convert this distance to meters, we need to divide it by 100 (1m = 100 cm), so the distance between the parallel sides is:

$15 cm / 100 = 0.15 m$

To find the area of the trapezoid, we can use the formula:

$Area = (a + b)h/2$

where a and b are the lengths of the parallel sides, and h is the distance between them.

So, the area of the trapezoid is:

Area =$(10 m + 25 m) * 0.15 m / 2$

=$(35 m) * 0.15 m / 2$

=$5.25 m^2$

Now, the cost of watering the field is given by the rate of watering per square meter multiplied by the area of the field. So,

Cost = $4 * 5.25 m^2 = 21 rs.$

Therefore, the cost of watering the trapezoidal field is 21 rs.

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