Question

find the cost of watering a trapezoidal field whose parallel sides are 10m and 25m respectively ,the perpendicular distance between them is 15 cm and the rate of watering is ₹4 per m.​

Answer 1

$\huge\star\underline\mathfrak\green{Answer:-}$

Given the parallel sides as 10 m & 25 m.

=1000 cm & 2500 cm

And the distance between them = 15 cm

So the area of the trapezium = ½ × 15 ×(1000+2500) cm²

= ½ × 15 ×3500 cm²

= 15 × 1750 cm²

= 26250 cm²

=2.625 m²

₹4 costs per 1 square metre watering.

So 2.625 square metre will cost = ₹2.625 × 4

= ₹ 10.5

Answer 2

Answer:

Considering the distance between parallel sides (h) = 15 m

Let one parallel side of the trapezoid be `a` = 10m

Another parallel side be `b` = 25m

The height that is the distance between the parallel sides = 15m

Area = [(a+b)/2]h

= [(10+25)/2 × 15] m²

= [35/2 × 15] m²

= [17.5 × 15]m²

= 262.5 m²

Cost of watering one m² area = Rs 4

Cost of watering 262.5 m² area = Rs 1050