Question

Find the cost of watering a trapezoidal field whose parallel sides are 10 m and
25 dm, respectively, the perpendicular distance between them is 200 em and the
rate of watering is 6 per cm square ?​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

$\star\large\mathcal{\underline{\underline{PLEASE \: }}}\large\mathcal\red{\underline{\underline{F}}}\large\mathcal\green{\underline{\underline{OLL}}}\large\mathcal\pink{\underline{\underline{OW \: }}}\large\mathcal\blue{\underline{\underline{ME}}}\star$

Step-by-step explanation:

$Let \: ABCD \: Be \: the \\ \: trapezoidal \: field$

$with \: height = 200m \: \: \: \: \: \: \: \: \: \: [see \: above \: image]$

$a = 10m$

$b = 25m$

$Area \: of \: trapezium = \frac{1}{2} (a+b)h$

$= \frac{1}{2} × (10+25)×200m²$

$= 25× 100m²$

$= 2500m²$

$converting \: into \: cm²:$

$=> 2500 × 100 × 100cm²$

$= 25,000,000cm²$

$now , rate \: of \: watering \: 1cm² = 1×6$

$= 25,000,000×6$

$= Rs.150,000,000$

$therefore , \: \: the \: cost \: of \: watering \: \\ the \: trapezoidal \: \\ field \: is \: Rs.150,000,000.$

$please \: like \: my \: answer \\ \&\\ mark \: me \: brainliest \: please \: :)))$

$\star\large\mathcal{\underline{\underline{PLEASE \: }}}\large\mathcal\red{\underline{\underline{F}}}\large\mathcal\green{\underline{\underline{OLL}}}\large\mathcal\pink{\underline{\underline{OW \: }}}\large\mathcal\blue{\underline{\underline{ME}}}\star$

$\star \: i \: hope \: you \: will \: understand \: me\star$