Question

Find the cost of watering a trapezoidal field whose parallel sides are 10 m and 25 m respectively, the
perpendicular distance between them is 15 cm and the rate of watering is 4 per m.​

Answer 1

Answer:

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Step-by-step explanation:

$Given , \: sides , \: a= 10m \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: b = 25m$

$and, \: height \: of \: Trapezium = 15cm= \frac{15}{100} =0.15m$

$Area \: of \: Trapezium= \frac{1}{2} (a+b)×h$

$=> \frac{1}{2} ×(10+25)×0.15m²$

$= \frac{1}{2} ×35×0.15m²$

$= \frac{1}{2} ×5.25m²$

$= 2.625m²$

$Now, \: cost \: of \: watering \: \: 1 \: m²=₹(1×4)$

$=> ₹(2.625×4)$

$= ₹10.5$

$therefore, \: cost \: of \: watering \\ a \: trapezoidal \: field \: is \: ₹10.5.$

$please \: like \: my \: answer \\ \&\\ mark \: me \: brainliest \: please \: :)))$

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