Question

find the cost of white-washing a trapezoidal wall whose parallel sides are 65m and 72m and non parallel sides are equal to 250dm. given the rate of white washing is Rupees 5/m²​

Answer 1

Answer:

250dm = 25m height = [√{25² + {(72 - 65)/2}²] = √[625 + 12.25] = 25.24 m

So, Area of trapezium = (1/2) × (65 + 72) × (25.24) = 1728.94 sq.m

Therefore, cost of white washing Rs.5/m² = 1728.94/5 = Rs. 345.788

Step-by-step explanation:

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Answer 2

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250 dm = 25 m

Length of parallel sides are 65 m and 72 m

Height = √25²+(72-65)²

= √625+7²

=√625+49

= √674

= 25.961 m

area of Trapezium = (1÷2) × sum of parallel side x distance between them

25.961

= (1-2) × (65+72) ×

= 1778.3285 m²

Therefore cost of painting the wall = area of wall x cost

1778.3285x155

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275640.9175 Rs or Paise