Question

Find the cost price of an article if it was sold for ₹40,gaining one-eighth of the cost price.

Answer is ₹35.50 plz step by step explanation
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Answer 1

GIVEN :-

• S.P of article = ₹ 40
• Profit = 1/8 of C.P

TO FIND :-

• The cost price of the article (C.P)

SOLUTION :-

⛥ Let the cost price be ₹ x

$\to \rm profit \: = \dfrac{1}{8} \timesC.P \\ \\ \to \rm profit \: = \dfrac{1}{8} x \\ \\ \implies \boxed{ \red{ \bf \:S.P \: = \:P \: + \:C.P }}$

➻ Now substitute the values,

$\to \rm \: 40 = x + \dfrac{1}{8} x \\ \\ \to \rm \: 40 = \dfrac{8x + x}{8} \\ \\ \to \rm \: 40 = \dfrac{9x}{8} \\ \\ \to \rm \: 9x = 40 \times 8 \\ \\ \to \rm \: 9x = 320 \\ \\ \to \rm \: x = \dfrac{320}{9} \\ \\ \to \boxed{ \red{ \rm \: x \: = 35.55}}$

Hence the cost price is ₹ 35.55

ADDITIONAL INFORMATION :-

$\boxed{\begin{minipage}{6cm} \\ \bf{ \underline{Some Formulae}} \\ \\ \rightarrow \quad \sf P = \dfrac{100 \times S.I}{R \times T} \\ \\ \\ \rightarrow \quad T = \dfrac{100 \times S.I}{P \times R} \\ \\ \\ \rightarrow \quad R = \dfrac{100 \times S.I}{P \times T} \\ \\ \\ \rightarrow \quad A = P + S.I \\ \\ \\ \rightarrow \quad S.I = \dfrac{P \times R \times T}{100} \\ \end{minipage}}$

Answer 2

Step-by-step explanation:

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