Question

Find the cost price, when :
(it) selling price = 690, profit = 15% . please solve it if u solved it I will follow you ​

Answer 1

$\huge{ \pink{\bigstar{\underline{\underline{Answer}}}}}$

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★Given:—

SP = 690

Profit = 15%

★To Find:—

CP = ?

★FORMULA:—

$\implies \large{\red{\bf{ </em></strong><strong><em>CP</em></strong><strong><em>=</em></strong><strong><em>\frac{</em></strong><strong><em>SP</em></strong><strong><em> \times 100}{100 + </em></strong><strong><em>Profit</em></strong><strong><em>} }}}$

★Solving By Applying The Formula:—

$\implies \large{\blue{\bf{ \frac{SP \times 100}{100 + Profit} = \frac{690 \times 100}{100 + 15} }}}$

$\implies \large{\blue{\bf{ \frac{690 \times 100}{100 + 15} = \frac{69000}{115} }}}$

$\implies \large{\blue{\bf{ \frac{ \not{69000}}{ \not{115}} }}}$

$\implies \large{\blue{\bf{ \frac{ \not{69000}}{ \not{115}} = 600}}}$

$\implies \large{\red{\bf{Hence, \: the \: CP \: is \:₹\: 600 \: rupees.}}}$

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Answer 2

Answer:

Required cost price is 240 rupees.

Step-by-step explanation:

Given selling price is 690 rupees and profit is 15%.

Let cost price be x.

We know,profit = Selling price-Cost price

According to question,

$690 - x = \frac{15}{100} \times x$

$600 - x = \frac{15x}{10}$

By cross multiplication,

$10(600 - x) = 15x$

$6000 - 10x = 15x$

Now we are separating all variable and constant part,

$15x + 10x = 6000$

$25x = 6000$

$x = \frac{6000}{25} = 240$

So cost price is 240 rupees.