Question

Find the couple acting on the shaft of a electric motor when developing a power 9420 w at a speed 300 revolution per minute.​

Answer 1

Given:

P = 9420 w = 9.420Kw

Speed (N)= 300 rpm

To find:

Couple acting on the shaft

Solution:

$D = \sqrt[a]{\frac{ 1.33 * 10^6 * P}{N}}$

D = $\sqrt[a]{\frac{1.33 * 10^6 * 9.420}{300} }$

D = 204.35mm