find the couple acting on the shaft of an eletric motor when developing a power 6280watt a speed 300 resolution per minute
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Answer:
P = 9420 w = 9.420Kw
Speed (N)= 300 rpm
To find:
Couple acting on the shaft
Solution:
D = \sqrt[a]{\frac{ 1.33 * 10^6 * P}{N}}D=
a
N
1.33∗10
6
∗P
D = \sqrt[a]{\frac{1.33 * 10^6 * 9.420}{300} }
a
300
1.33∗10
6
∗9.420
D = 204.35mm
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