Question

Find the critical angle of a medium of refractive index 1.65

Answer 1

May this help you mate!!

n=1/sinc

where n: refractive index

and c: critical angle.

Therefore, 1/n= sinc

So, c = sin inverse of (1/n)

c = sin inverse of (1/1.65)

c=37.3052009686°

Answer 2

Answer:

37.30°.

Given:

Refractive index = 1.65.

To Find:

Critical angle of medium.

Step-by-step explanation:

Now,

• Critical angle: it is angle of incidence at which the the angle of refraction is 90°. hence, the light will remain inside the medium.

• C = $sin^{-1}$(1/μ)   where c is critical angle

                       and μ is refractive index of medium.

• put value of μ in the above formula, we get,

    C = $sin^{-1}$(1/1.65)

    sin C = (1/1.65)

    sin 37.30° = 1/1.65

    C = 37.30°

Hence, the critical angle of medium is 37.30°.