Question

Find the critical angle of light going from paraffin oil to air. Given that the refractive index of paraffin oil with respect to air is 1.44.
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Answer 1

The critical angle of light going from paraffin oil to air is 43.97 degrees.

Explanation:

Given that, the refractive index of paraffin oil with respect to air is 1.44. The relation between the refractive index and the critical angle is given by :

$sin\theta_c=\dfrac{1}{n}$

$sin\theta_c=\dfrac{1}{1.44}$

$sin\theta_c=0.6944$

$\theta_c=sin^{-1}(0.6944)$

$\theta_c=43.97^{\circ}$

So, the critical angle of light going from paraffin oil to air is 43.97 degrees. Hence, this is the required solution.

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Answer 2

Answer:

Given that, the refractive index of paraffin oil with respect to air is 1.44. The relation between the refractive index and the critical angle is given by :

sin\theta_c=\dfrac{1}{n}sinθc=n1

sin\theta_c=\dfrac{1}{1.44}sinθc=1.441

sin\theta_c=0.6944sinθc=0.6944

\theta_c=sin^{-1}(0.6944)θc=sin−1(0.6944)

\theta_c=43.97^{\circ}θc=43.97∘

approximately 44 degree