Physics, asked by akalambe51, 11 months ago

find the cross product of 3i+4j+3kand 2i-4j+5k explain​

Answers

Answered by kaynat87
1

Answer:

let A = 3i+4j+3k

let A = 3i+4j+3kB= 2i-4j+5k

let A = 3i+4j+3kB= 2i-4j+5kA×B= (3i+4j+3k)×(2i-4j+5k)

let A = 3i+4j+3kB= 2i-4j+5kA×B= (3i+4j+3k)×(2i-4j+5k)= 3i×(2i-4j+5k)

let A = 3i+4j+3kB= 2i-4j+5kA×B= (3i+4j+3k)×(2i-4j+5k)= 3i×(2i-4j+5k)multiply kr sakte ho na

let A = 3i+4j+3kB= 2i-4j+5kA×B= (3i+4j+3k)×(2i-4j+5k)= 3i×(2i-4j+5k)multiply kr sakte ho naagge same step follow kro

let A = 3i+4j+3kB= 2i-4j+5kA×B= (3i+4j+3k)×(2i-4j+5k)= 3i×(2i-4j+5k)multiply kr sakte ho naagge same step follow kro(i×i) = 0

let A = 3i+4j+3kB= 2i-4j+5kA×B= (3i+4j+3k)×(2i-4j+5k)= 3i×(2i-4j+5k)multiply kr sakte ho naagge same step follow kro(i×i) = 0(j×j) = 0

let A = 3i+4j+3kB= 2i-4j+5kA×B= (3i+4j+3k)×(2i-4j+5k)= 3i×(2i-4j+5k)multiply kr sakte ho naagge same step follow kro(i×i) = 0(j×j) = 0(k×k)= 0

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