Physics, asked by Anonymous, 10 months ago

Find the cross product of the given vectors.

A = 4 i - j + k and B = i - 2 j - 4 k .

Answers

Answered by raopragathi100
0

Answer:

Explanation:

THE CROSS PRODUCT OF

A =4 i- j+ k AND B = i - 2 j - 4 k   IS GIVEN BY USING THE DETERMINANT METHOD

: SO THE ANSWER IS 2 i + 17 j - 7 k

Answered by Anonymous
10

Answer:

\displaystyle \text{$\vec A \times \vec B=6\hat{i}+17\hat{j}-7\hat{k}$}

Explanation:

Given :

\displaystyle \text{$\vec A=4\hat{i}-\hat{j}+\hat{k}$ and }\\\\\displaystyle \text{$\vec B=\hat{i}-2\hat{j}-4\hat{k}$}

Here angle is not given.

So we will use determinant method.

                                                             

           i                     j                          k

          4                   - 1                          1

           1                     -2                       - 4

                                                                 

\displaystyle \text{$\vec A \times \vec B=\hat{i} (4-(-2))-\hat{j}(-16-1)+\hat{k}(-8-(-1))$}\\\\\\\displaystyle \text{$\vec A \times \vec B=\hat{i} (4+2))-\hat{j}(-17)+\hat{k}(-8+1))$}\\\\\\\displaystyle \text{$\vec A \times \vec B=\hat{i} (6))-\hat{j}(-17)+\hat{k}(-7))$}\\\\\\\displaystyle \text{$\vec A \times \vec B=6\hat{i}+17\hat{j}-7\hat{k}$}

Thus we get answer.

Extra points :

In case of cross product

\displaystyle \text{$\hat{i}\times\hat{i}=0$}\\\\\displaystyle \text{$\hat{j}\times\hat{j}=0$}\\\\\displaystyle \text{$\hat{k}\times\hat{k}=0$}\\\\\displaystyle \text{$\hat{i}\times\hat{j}=1$}\\\\\displaystyle \text{$\hat{j}\times\hat{k}=1$}\\\\\displaystyle \text{$\hat{k}\times\hat{i}=1$}

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