find the cube 2a-b-c
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Answer:
4a²+b²+c²-2(2ab-bc+2ac)
step by step explanation
(2a-b-c)²
(2a)²+(-b)²+(-c)²+2×2a×(-b)+2×(-b)×(-c)+2×(-c)×2a
=4a²+b²+c²-4ab+2bc-4ac
=4a²+b²+c²-2(2ab-bc+2ac)
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