find the cube of 11 by adding three consecutive odd numbers
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Answered by
7
Answer:
this is the answer
Step-by-step explanation:
(2x+1)+(2x+3)+(2x+5)=11³
or, 6x+9=1331
or, x=220.3≈220
now, 1st odd no.: 220×2+1=441
2nd odd no.:220×2+3=443
3rd no.:(we have taken x as approximate value to find and odd number)
so, third number=1331-(443+441)
=447
therefore: numbers are 441,443 and 447
Answered by
2
Answer:
wait Karo bro bhejta hu
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